initialization order in Kotlin

During construction of a new instance of a derived class, the base class initialization is done as the first step (preceded only by evaluation of the arguments for the base class constructor) and thus happens before the initialization logic of the derived class is run.
```
open class Base(val name: String) {
    init { println("Initializing Base") }
    open val size: Int = 
        name.length.also { println("Initializing size in Base: $it") }
}

class Derived(
    name: String,
    val lastName: String,
) : Base(name.capitalize().also { println("Argument for Base: $it") }) {
    init { println("Initializing Derived") }
    override val size: Int =
        (super.size + lastName.length).also { println("Initializing size in Derived: $it") }
}
```
It means that, by the time of the base class constructor execution, the properties declared or overridden in the derived class are not yet initialized. If any of those properties are used in the base class initialization logic (either directly or indirectly, through another overridden open member implementation), it may lead to incorrect behavior or a runtime failure. When designing a base class, you should therefore avoid using open members in the constructors, property initializers, and init blocks.
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